-30=x^2+13x

Solution for -30=x^2+13x equation:

-30=x^2+13x

We move all terms to the left:

-30-(x^2+13x)=0

We get rid of parentheses

-x^2-13x-30=0

We add all the numbers together, and all the variables

-1x^2-13x-30=0

a = -1; b = -13; c = -30;
Δ = b2-4ac
Δ = -132-4·(-1)·(-30)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-7}{2*-1}=\frac{6}{-2}
=-3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+7}{2*-1}=\frac{20}{-2}
=-10
$